Before you know it, Valentine's Day will be here, and it turns out that one of the best cities in all of America for the big day is in Illinois.

When you take a closer look, you'd think, "Well, sure, of course, Chicago would be near the top when it comes to a study like this."

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Not necessarily, just because the population is so big.

This Illinois City Is a Better Destination for Valentine's Day Than Los Angeles and New York.

As a matter of fact, the third biggest city in America (Chicago) is ranked higher than the two cities that have larger populations, New York City and Los Angeles.

Lake Shore Drive & Chicago Skyline At Night
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Keep Reading: Free Fun: Tons of No Charge Museum Days for Illinois Residents This February

It is a bit surprising that among some of the more metropolitan cities, like San Francisco (ranked #1 overall), Seattle (#2), and San Diego (#3), Scottsdale in Arizona is ranked #7. That city had a higher score than Chicago.

What City in Illinois is the Best for Valentine's Day?

Using key metrics like Budget, Activities, Gift Accessibility, and Weather Forecast, Chicago was ranked #13.

Funny Valentine's Day, series of different approaching acts
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Budget and, most importantly, Weather Forecast killed any chances of it being a top 10 Valentine's Day destination.

Keep Reading: Snow, Sleet, and Freezing Rain Expected in Northern Illinois This Week

Chicago was the only city to make WalletHub's Top 100, while two in Wisconsin were represented, Madison and Milwaukee.

If you are going to celebrate Valentine's Day in Madison this year, be sure to check out the highest-rated restaurants in Madison before finalizing plans.

Highest-rated restaurants in Madison, according to Tripadvisor

Stacker compiled a list of the highest rated restaurants in Madison from Tripadvisor.

Gallery Credit: Stacker

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