Four of America’s Top Five Drunkest Cities are in Wisconsin

I mean, I always knew folks in Wisconsin could drink but whoa, I wasn't prepared for how much.

According to 24/7 Wall Street people in Wisconsin drink, like, a lot.

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I mean, there's stuff to do, so I'm not sure exactly why Wisconsinites tie one on but they do and apparently, they do often.

24/7 Wall Street profiled The 50 Drunkest Cities in America, and nearly a staggering 25% of the cities in the list are in America's Dairyland.

By comparison, there wasn't one city in Illinois that made the top 50.

Janesville-Beloit came in 18th overall, where apparently 25.1% of the population drinks excessively.

Sidling up to Janesville-Beloit is Racine, ranked 17th, where 25.2% of the town is drinking too much.

Milwaukee-Waukesha, Eau Claire, and Wausau-Weston are ranked 14th, 13th, and 12th respectively as the drunkest cities in America according to 24/7 Wall Street.

When you get to the top 10, hold on to your hat because 7 of the 10 drunkest cities in America are all in Wisconsin.

#9 La Crosse-Onalaska
#7 Fond du Lac
#6 Madison
#5 Oshkosh-Neenah
#4 Green Bay
#3 Sheboygan
#1 Appleton

Keep in mind, this list isn't the drunkest cities in Wisconsin, this is the drunkest cities in the United States.

In Appleton, the population considered to be drinking excessively is at 30.2%. Comparatively, the national average is 19.2%.

24/7 Wall Street says Appleton's population is 237,974 meaning about 80,000 people are considered to be binge drinkers.

According to the CDC, excessive or binge drinking occurs when a man has five or more drinks on one occasion and a woman has four.

If you or someone you know needs help call the Substance Abuse and Mental Health Administration Hotline at 800.662.4357.